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Possible Duplicate: Objects vs arrays in Javascript for key value pairs I have a variable in JavaScript which I am using like a hash  I can initialize it like: var selected = []; or var selec   Apr 13, 2012 · Little bit out of topic, but mentioning it here for reference  "let" is very similar to "var" and is supported in Mozilla  The main difference is that the scope of a var variable is the entire enclosing function where as "let" is restricted to its blockMay 25, 2010 · C# is a strictly strongly typed language  var was introduced for compile-time type-binding for anonymous types yet you can use var for primitive and custom types that are already known at design time  At runtime there's nothing like var, it is replaced by an actual type that is either a reference type or value type  When you say,Aug 29, 2013 · 123 That description of  var is self-contradictory   var contains things that are prone to change, such as websites, temporary files ( var tmp) and databases  The name is an abbreviation of "variable" Apr 18, 2009 · Scoping rules The main difference is scoping rules  Variables declared by var keyword are scoped to the immediate function body (hence the function scope) while let variables are scoped to the immediate enclosing block denoted by { } (hence the block scope) Jun 27, 2016 · A program logs some message in directory  var mobile Containers Data Application on iPhone  Is there any way I can get access to this directory without jailbreaking iPhone?Aug 9, 2013 · What the title says: what does it mean to encapsulate a variable in {}, "", or "{}"? I haven't been able to find any explanations online about this - I haven't been able to refer to them except for   Jun 11, 2020 · var is a "contextual keyword" in C# meaning you can only use it as a local variable implicitly in the context of the same class that you are using the variable tldr; Although both var++ and ++var increment the variable they are applied to, the result returned by var++ is the value of the variable before incrementing, whereas the result returned by ++var is the value of the variable after the increment is applied  Further Explanation When ++var or var++ form a complete statement (as in your examples) there is no difference between the two  For example    Dec 15, 2011 · I'm reading " Bash Guide for Beginners "  It says: If the first character of PARAMETER is an exclamation point, Bash uses the value of the variable formed from the rest of PARAMETER as the name of the variable; this variable is then expanded and that value is used in the rest of the substitution, rather than the value of PARAMETER itself  This is known as indirect expansion  The example given is:

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